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authorEric Biggers <ebiggers@google.com>2016-12-05 11:12:44 -0800
committerGreg Kroah-Hartman <gregkh@linuxfoundation.org>2017-11-30 08:39:11 +0000
commitd612bee05b031e6cac5606aff6e95ce7cd8104e4 (patch)
tree9ef9a04d06ee1c63fac970899747953c1ca8343e /fs/crypto
parente7918c60da9c1d081f3f19cb46301b04e1f085c9 (diff)
fscrypt: use ENOKEY when file cannot be created w/o key
[ Upstream commit 54475f531bb8d7078f63c159e5e0615d486c498c ] As part of an effort to clean up fscrypt-related error codes, make attempting to create a file in an encrypted directory that hasn't been "unlocked" fail with ENOKEY. Previously, several error codes were used for this case, including ENOENT, EACCES, and EPERM, and they were not consistent between and within filesystems. ENOKEY is a better choice because it expresses that the failure is due to lacking the encryption key. It also matches the error code returned when trying to open an encrypted regular file without the key. I am not aware of any users who might be relying on the previous inconsistent error codes, which were never documented anywhere. This failure case will be exercised by an xfstest. Signed-off-by: Eric Biggers <ebiggers@google.com> Signed-off-by: Theodore Ts'o <tytso@mit.edu> Signed-off-by: Sasha Levin <alexander.levin@verizon.com> Signed-off-by: Greg Kroah-Hartman <gregkh@linuxfoundation.org>
Diffstat (limited to 'fs/crypto')
-rw-r--r--fs/crypto/fname.c4
1 files changed, 2 insertions, 2 deletions
diff --git a/fs/crypto/fname.c b/fs/crypto/fname.c
index d1bbdc9dda76..e14bb7b67e9c 100644
--- a/fs/crypto/fname.c
+++ b/fs/crypto/fname.c
@@ -332,7 +332,7 @@ int fscrypt_fname_usr_to_disk(struct inode *inode,
* in a directory. Consequently, a user space name cannot be mapped to
* a disk-space name
*/
- return -EACCES;
+ return -ENOKEY;
}
EXPORT_SYMBOL(fscrypt_fname_usr_to_disk);
@@ -367,7 +367,7 @@ int fscrypt_setup_filename(struct inode *dir, const struct qstr *iname,
return 0;
}
if (!lookup)
- return -EACCES;
+ return -ENOKEY;
/*
* We don't have the key and we are doing a lookup; decode the